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1.8x^2+5x+1.7=0
a = 1.8; b = 5; c = +1.7;
Δ = b2-4ac
Δ = 52-4·1.8·1.7
Δ = 12.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{12.76}}{2*1.8}=\frac{-5-\sqrt{12.76}}{3.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{12.76}}{2*1.8}=\frac{-5+\sqrt{12.76}}{3.6} $
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